What are the solutions to the equation 4x^2+12x=4x-9 ?

The solutions to the equation 4x^2+12x=4x-9 are x=-1+i(sqrt(5))/2 ,x=-1-i(sqrt(5))/2

Find the zeros of 4x^2+12x=4x-9

The zeros of 4x^2+12x=4x-9 are x=-1+i(sqrt(5))/2 ,x=-1-i(sqrt(5))/2

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4 x^{2} + 12 x = 4 x - 9

x = - 1 + i \frac{5}{2}, x = - 1 - i \frac{5}{2}

Solution steps

4 x^{2} + 12 x = 4 x - 9

Move

9

to the left side

4 x^{2} + 12 x + 9 = 4 x

Move

4 x

to the left side

4 x^{2} + 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

Simplify

8^{2} - 4 \cdot 4 \cdot 9 : 45 i

x_{1, 2} = \frac{- 8 \pm 4 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 5 i}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 5 i}{2 \cdot 4}

x = \frac{- 8 + 4 5 i}{2 \cdot 4} : - 1 + i \frac{5}{2}

x = \frac{- 8 - 4 5 i}{2 \cdot 4} : - 1 - i \frac{5}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{5}{2}, x = - 1 - i \frac{5}{2}

x^{2} - 16 x + 16 = 0

3 x^{2} - 9 x - 2 = 0

5 x^{2} + 7 x - 5 = 0

5 x^{2} - 8 x + 7 = 0

x^{2} + 4 x + 0 = 0

What are the solutions to the equation 4x^2+12x=4x-9 ?
The solutions to the equation 4x^2+12x=4x-9 are x=-1+i(sqrt(5))/2 ,x=-1-i(sqrt(5))/2
Find the zeros of 4x^2+12x=4x-9
The zeros of 4x^2+12x=4x-9 are x=-1+i(sqrt(5))/2 ,x=-1-i(sqrt(5))/2