What are the solutions to the equation 3t^2+10t+5=0 ?

The solutions to the equation 3t^2+10t+5=0 are t=(-5+sqrt(10))/3 ,t=-(5+sqrt(10))/3

Find the zeros of 3t^2+10t+5=0

The zeros of 3t^2+10t+5=0 are t=(-5+sqrt(10))/3 ,t=-(5+sqrt(10))/3

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3 t^{2} + 10 t + 5 = 0

t = \frac{- 5 + 10}{3}, t = - \frac{5 + 10}{3}

Decimal Notation

t = - 0.61257 \dots, t = - 2.72075 \dots

Solution steps

3 t^{2} + 10 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 5 = 210

t_{1, 2} = \frac{- 10 \pm 2 10}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- 10 + 2 10}{2 \cdot 3}, t_{2} = \frac{- 10 - 2 10}{2 \cdot 3}

t = \frac{- 10 + 2 10}{2 \cdot 3} : \frac{- 5 + 10}{3}

t = \frac{- 10 - 2 10}{2 \cdot 3} : - \frac{5 + 10}{3}

The solutions to the quadratic equation are:

t = \frac{- 5 + 10}{3}, t = - \frac{5 + 10}{3}

x, x^{2} - k x + 196 = 0

2 (x - 3) (4 x - 1) = (4 x - 6)^{2} - 4 (6 + x)

x, 8 x^{2} + 9 y^{2} + 288 = 0

x^{2} + 28 x = - 192

x^{2} - 2 x + 2 = 2 x

What are the solutions to the equation 3t^2+10t+5=0 ?
The solutions to the equation 3t^2+10t+5=0 are t=(-5+sqrt(10))/3 ,t=-(5+sqrt(10))/3
Find the zeros of 3t^2+10t+5=0
The zeros of 3t^2+10t+5=0 are t=(-5+sqrt(10))/3 ,t=-(5+sqrt(10))/3