What are the solutions to the equation solvefor y,x=1-y^2 ?

The solutions to the equation solvefor y,x=1-y^2 are y=sqrt(-x+1),y=-sqrt(-x+1)

Find the zeros of solvefor y,x=1-y^2

The zeros of solvefor y,x=1-y^2 are y=sqrt(-x+1),y=-sqrt(-x+1)

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solve for

y, x = 1 - y^{2}

y = - x + 1, y = - - x + 1

Solution steps

x = 1 - y^{2}

Switch sides

1 - y^{2} = x

Move

1

to the right side

- y^{2} = x - 1

Divide both sides by

- 1

y^{2} = - x + 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - x + 1, y = - - x + 1

a^{2} + a

(x - 5)^{2} = 27

x^{2} + 7 x = - 6

t, h = \frac{1}{2} g t^{2} + v_{0} t

4 x^{2} - 20 x + 25 = 32

What are the solutions to the equation solvefor y,x=1-y^2 ?
The solutions to the equation solvefor y,x=1-y^2 are y=sqrt(-x+1),y=-sqrt(-x+1)
Find the zeros of solvefor y,x=1-y^2
The zeros of solvefor y,x=1-y^2 are y=sqrt(-x+1),y=-sqrt(-x+1)