What are the solutions to the equation x^2+7x+2=0 ?

The solutions to the equation x^2+7x+2=0 are x=(-7+sqrt(41))/2 ,x=(-7-sqrt(41))/2

Find the zeros of x^2+7x+2=0

The zeros of x^2+7x+2=0 are x=(-7+sqrt(41))/2 ,x=(-7-sqrt(41))/2

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x^{2} + 7 x + 2 = 0

x = \frac{- 7 + 41}{2}, x = \frac{- 7 - 41}{2}

Decimal Notation

x = - 0.29843 \dots, x = - 6.70156 \dots

Solution steps

x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 2 = 41

x_{1, 2} = \frac{- 7 \pm 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 41}{2 \cdot 1}, x_{2} = \frac{- 7 - 41}{2 \cdot 1}

x = \frac{- 7 + 41}{2 \cdot 1} : \frac{- 7 + 41}{2}

x = \frac{- 7 - 41}{2 \cdot 1} : \frac{- 7 - 41}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 41}{2}, x = \frac{- 7 - 41}{2}

\frac{6}{2 - i}

- \frac{18}{9 x y} + \frac{7}{2 x} - \frac{2}{3 x ^{2}}

7 y - 8 > 6

\frac{1}{0.0001}

- \frac{3}{2} w > - 11

What are the solutions to the equation x^2+7x+2=0 ?
The solutions to the equation x^2+7x+2=0 are x=(-7+sqrt(41))/2 ,x=(-7-sqrt(41))/2
Find the zeros of x^2+7x+2=0
The zeros of x^2+7x+2=0 are x=(-7+sqrt(41))/2 ,x=(-7-sqrt(41))/2