What are the solutions to the equation x^2-2x+20=1 ?

The solutions to the equation x^2-2x+20=1 are x=1+3sqrt(2)i,x=1-3sqrt(2)i

Find the zeros of x^2-2x+20=1

The zeros of x^2-2x+20=1 are x=1+3sqrt(2)i,x=1-3sqrt(2)i

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x^{2} - 2 x + 20 = 1

x = 1 + 32 i, x = 1 - 32 i

Solution steps

x^{2} - 2 x + 20 = 1

Move

1

to the left side

x^{2} - 2 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 19 : 62 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6 2 i}{2 \cdot 1} : 1 + 32 i

x = \frac{- ( - 2 ) - 6 2 i}{2 \cdot 1} : 1 - 32 i

The solutions to the quadratic equation are:

x = 1 + 32 i, x = 1 - 32 i

z^{2} - 10 z + 25 = 0

x^{2} - 3 x + 1 = 0

2 n^{2} - 8 n = 256

4 x^{2} - 9 x + 6 = 0

2 x^{2} = - x

What are the solutions to the equation x^2-2x+20=1 ?
The solutions to the equation x^2-2x+20=1 are x=1+3sqrt(2)i,x=1-3sqrt(2)i
Find the zeros of x^2-2x+20=1
The zeros of x^2-2x+20=1 are x=1+3sqrt(2)i,x=1-3sqrt(2)i