What are the solutions to the equation -(x-1)(x-7)=0 ?

The solutions to the equation -(x-1)(x-7)=0 are x=1,x=7

Find the zeros of -(x-1)(x-7)=0

The zeros of -(x-1)(x-7)=0 are x=1,x=7

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- (x - 1) (x - 7) = 0

x = 1, x = 7

Solution steps

- (x - 1) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 7 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 7 = 0 : x = 7

The solutions to the quadratic equation are:

x = 1, x = 7

- x^{2} = - 12 x + 6

3 r^{2} + 2 r + 1 = 0

r, V = π r^{2} \frac{h}{3}

62 = - 4.9 t^{2} + 19.6 t + 58.8

t^{2} - 81 = 0

What are the solutions to the equation -(x-1)(x-7)=0 ?
The solutions to the equation -(x-1)(x-7)=0 are x=1,x=7
Find the zeros of -(x-1)(x-7)=0
The zeros of -(x-1)(x-7)=0 are x=1,x=7