What are the solutions to the equation x^2-12x-9=0 ?

The solutions to the equation x^2-12x-9=0 are x=3(2+sqrt(5)),x=3(2-sqrt(5))

Find the zeros of x^2-12x-9=0

The zeros of x^2-12x-9=0 are x=3(2+sqrt(5)),x=3(2-sqrt(5))

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x^{2} - 12 x - 9 = 0

x = 3 (2 + 5), x = 3 (2 - 5)

Decimal Notation

x = 12.70820 \dots, x = - 0.70820 \dots

Solution steps

x^{2} - 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 9) = 65

x_{1, 2} = \frac{- ( - 12 ) \pm 6 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 5}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 6 5}{2 \cdot 1}

x = \frac{- ( - 12 ) + 6 5}{2 \cdot 1} : 3 (2 + 5)

x = \frac{- ( - 12 ) - 6 5}{2 \cdot 1} : 3 (2 - 5)

The solutions to the quadratic equation are:

x = 3 (2 + 5), x = 3 (2 - 5)

y^{2} - 2 y + 3 = 0

2 X^{2} - 5 X - 3 = 0

2 x^{2} - 5 x - 42 = 0

\frac{1}{6} t^{2} - 25 = 0

s^{2} + 4 s + 8

What are the solutions to the equation x^2-12x-9=0 ?
The solutions to the equation x^2-12x-9=0 are x=3(2+sqrt(5)),x=3(2-sqrt(5))
Find the zeros of x^2-12x-9=0
The zeros of x^2-12x-9=0 are x=3(2+sqrt(5)),x=3(2-sqrt(5))