What are the solutions to the equation 4x^2-6x+7=0 ?

The solutions to the equation 4x^2-6x+7=0 are x= 3/4+i(sqrt(19))/4 ,x= 3/4-i(sqrt(19))/4

Find the zeros of 4x^2-6x+7=0

The zeros of 4x^2-6x+7=0 are x= 3/4+i(sqrt(19))/4 ,x= 3/4-i(sqrt(19))/4

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4 x^{2} - 6 x + 7 = 0

x = \frac{3}{4} + i \frac{19}{4}, x = \frac{3}{4} - i \frac{19}{4}

Solution steps

4 x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

(- 6)^{2} - 4 \cdot 4 \cdot 7 : 219 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 19 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 19 i}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2 19 i}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2 19 i}{2 \cdot 4} : \frac{3}{4} + i \frac{19}{4}

x = \frac{- ( - 6 ) - 2 19 i}{2 \cdot 4} : \frac{3}{4} - i \frac{19}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} + i \frac{19}{4}, x = \frac{3}{4} - i \frac{19}{4}

x, 2 x^{2} + 2 x y + 2 y^{2} - 2 x - 10 y + 11 = 0

2 x (x - 3) = - 5

2 x (x - 3) = 10

n^{2} + 8^{2} = 1 2^{2}

6 x^{2} + 7 x - 1 = 0

What are the solutions to the equation 4x^2-6x+7=0 ?
The solutions to the equation 4x^2-6x+7=0 are x= 3/4+i(sqrt(19))/4 ,x= 3/4-i(sqrt(19))/4
Find the zeros of 4x^2-6x+7=0
The zeros of 4x^2-6x+7=0 are x= 3/4+i(sqrt(19))/4 ,x= 3/4-i(sqrt(19))/4