What are the solutions to the equation completesquare x^2+6x-4=0 ?

The solutions to the equation completesquare x^2+6x-4=0 are x=sqrt(13)-3,x=-sqrt(13)-3

Find the zeros of completesquare x^2+6x-4=0

The zeros of completesquare x^2+6x-4=0 are x=sqrt(13)-3,x=-sqrt(13)-3

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x^{2} + 6 x - 4 = 0

x = 13 - 3, x = - 13 - 3

Decimal Notation

x = 0.60555 \dots, x = - 6.60555 \dots

Solution steps

x^{2} + 6 x - 4 = 0

Move

4

to the right side

x^{2} + 6 x = 4

Rewrite in the form

(x + a)^{2} = b

(x + 3)^{2} = 13

For

the solutions are

f (x) = a, - a

Solve

x + 3 = 13 : x = 13 - 3

Solve

x + 3 = - 13 : x = - 13 - 3

The solutions to the quadratic equation are:

x = 13 - 3, x = - 13 - 3

x^{2} - 2 x + 1 = 3

x, x z + y z^{3} = 2 + x^{2} e^{y}

86 = 6 + 8 (x^{2})

x^{2} + 8 x + 4

x^{2} + 8 x + 2

What are the solutions to the equation completesquare x^2+6x-4=0 ?
The solutions to the equation completesquare x^2+6x-4=0 are x=sqrt(13)-3,x=-sqrt(13)-3
Find the zeros of completesquare x^2+6x-4=0
The zeros of completesquare x^2+6x-4=0 are x=sqrt(13)-3,x=-sqrt(13)-3