What are the solutions to the equation completesquare 3x^2-6x-1=0 ?

The solutions to the equation completesquare 3x^2-6x-1=0 are x= 2/(sqrt(3))+1,x=-2/(sqrt(3))+1

Find the zeros of completesquare 3x^2-6x-1=0

The zeros of completesquare 3x^2-6x-1=0 are x= 2/(sqrt(3))+1,x=-2/(sqrt(3))+1

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3 x^{2} - 6 x - 1 = 0

x = \frac{2}{3} + 1, x = - \frac{2}{3} + 1

Decimal Notation

x = 2.15470 \dots, x = - 0.15470 \dots

Solution steps

3 x^{2} - 6 x - 1 = 0

Move

1

to the right side

3 x^{2} - 6 x = 1

Divide both sides by

3

\frac{3 x ^{2} - 6 x}{3} = \frac{1}{3}

x^{2} - 2 x = \frac{1}{3}

Rewrite in the form

(x + a)^{2} = b

(x - 1)^{2} = \frac{4}{3}

For

the solutions are

f (x) = a, - a

Solve

x - 1 = \frac{4}{3} : x = \frac{2}{3} + 1

Solve

x - 1 = - \frac{4}{3} : x = - \frac{2}{3} + 1

The solutions to the quadratic equation are:

x = \frac{2}{3} + 1, x = - \frac{2}{3} + 1

0 = - x^{2} + 2 x + 8

9 x^{2} - 12 x + 4 = 4

4 x^{2} + b x - 27 = 0

- 7 x + 15 = 4 x^{2}

- (x + 2)^{2} = (x + 4)^{2}

What are the solutions to the equation completesquare 3x^2-6x-1=0 ?
The solutions to the equation completesquare 3x^2-6x-1=0 are x= 2/(sqrt(3))+1,x=-2/(sqrt(3))+1
Find the zeros of completesquare 3x^2-6x-1=0
The zeros of completesquare 3x^2-6x-1=0 are x= 2/(sqrt(3))+1,x=-2/(sqrt(3))+1