What are the solutions to the equation x^2+3x=x+7 ?

The solutions to the equation x^2+3x=x+7 are x=-1+2sqrt(2),x=-1-2sqrt(2)

Find the zeros of x^2+3x=x+7

The zeros of x^2+3x=x+7 are x=-1+2sqrt(2),x=-1-2sqrt(2)

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x^{2} + 3 x = x + 7

x = - 1 + 22, x = - 1 - 22

Decimal Notation

x = 1.82842 \dots, x = - 3.82842 \dots

Solution steps

x^{2} + 3 x = x + 7

Move

7

to the left side

x^{2} + 3 x - 7 = x

Move

x

to the left side

x^{2} + 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 7) = 42

x_{1, 2} = \frac{- 2 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 2}{2 \cdot 1}

x = \frac{- 2 + 4 2}{2 \cdot 1} : - 1 + 22

x = \frac{- 2 - 4 2}{2 \cdot 1} : - 1 - 22

The solutions to the quadratic equation are:

x = - 1 + 22, x = - 1 - 22

x^{2} = 1 3^{2} - 1 2^{2}

5 x^{2} - 2 x - 2 = 0

3 x^{2} - 17 = 0

(x + 1) (x - 1) + 8 x^{2} = 4 x (x - 1)

x^{2} - 361 = 0

What are the solutions to the equation x^2+3x=x+7 ?
The solutions to the equation x^2+3x=x+7 are x=-1+2sqrt(2),x=-1-2sqrt(2)
Find the zeros of x^2+3x=x+7
The zeros of x^2+3x=x+7 are x=-1+2sqrt(2),x=-1-2sqrt(2)