What are the solutions to the equation completesquare x^2-8x-10=0 ?

The solutions to the equation completesquare x^2-8x-10=0 are x=sqrt(26)+4,x=-sqrt(26)+4

Find the zeros of completesquare x^2-8x-10=0

The zeros of completesquare x^2-8x-10=0 are x=sqrt(26)+4,x=-sqrt(26)+4

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x^{2} - 8 x - 10 = 0

x = 26 + 4, x = - 26 + 4

Decimal Notation

x = 9.09901 \dots, x = - 1.09901 \dots

Solution steps

x^{2} - 8 x - 10 = 0

Move

10

to the right side

x^{2} - 8 x = 10

Rewrite in the form

(x + a)^{2} = b

(x - 4)^{2} = 26

For

the solutions are

f (x) = a, - a

Solve

x - 4 = 26 : x = 26 + 4

Solve

x - 4 = - 26 : x = - 26 + 4

The solutions to the quadratic equation are:

x = 26 + 4, x = - 26 + 4

x (x + 2) + 5 = 3 (2 - x) + x - 4

x^{2} = 2^{2} + 1^{2}

3 x^{2} = - 54 x - 231

x^{2} - 10 = 8

2 x^{2} = 7 x - 3

What are the solutions to the equation completesquare x^2-8x-10=0 ?
The solutions to the equation completesquare x^2-8x-10=0 are x=sqrt(26)+4,x=-sqrt(26)+4
Find the zeros of completesquare x^2-8x-10=0
The zeros of completesquare x^2-8x-10=0 are x=sqrt(26)+4,x=-sqrt(26)+4