What are the solutions to the equation 4x^2-6=-12x ?

The solutions to the equation 4x^2-6=-12x are x=(-3+sqrt(15))/2 ,x=-(3+sqrt(15))/2

Find the zeros of 4x^2-6=-12x

The zeros of 4x^2-6=-12x are x=(-3+sqrt(15))/2 ,x=-(3+sqrt(15))/2

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4 x^{2} - 6 = - 12 x

x = \frac{- 3 + 15}{2}, x = - \frac{3 + 15}{2}

Decimal Notation

x = 0.43649 \dots, x = - 3.43649 \dots

Solution steps

4 x^{2} - 6 = - 12 x

Move

12 x

to the left side

4 x^{2} - 6 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 12 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 6) = 415

x_{1, 2} = \frac{- 12 \pm 4 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 4 15}{2 \cdot 4}, x_{2} = \frac{- 12 - 4 15}{2 \cdot 4}

x = \frac{- 12 + 4 15}{2 \cdot 4} : \frac{- 3 + 15}{2}

x = \frac{- 12 - 4 15}{2 \cdot 4} : - \frac{3 + 15}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 15}{2}, x = - \frac{3 + 15}{2}

3 (x^{2} - 4) = 0

x^{2} - 16 x + 1 = 0

x^{2} - 6 x = - 156

6 x^{2} - 72 = 0

2 x = 5 x^{2} - 3

What are the solutions to the equation 4x^2-6=-12x ?
The solutions to the equation 4x^2-6=-12x are x=(-3+sqrt(15))/2 ,x=-(3+sqrt(15))/2
Find the zeros of 4x^2-6=-12x
The zeros of 4x^2-6=-12x are x=(-3+sqrt(15))/2 ,x=-(3+sqrt(15))/2