What are the solutions to the equation (n+3)^2=0 ?

The solutions to the equation (n+3)^2=0 are n=-3

Find the zeros of (n+3)^2=0

The zeros of (n+3)^2=0 are n=-3

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(n + 3)^{2} = 0

n = - 3

Solution steps

(n + 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

n + 3 = 0 : n = - 3

The solution to the quadratic equation is:

n = - 3

\frac{1}{4} x - \frac{1}{5} (x - 3) = 5 x

100 = 32 x - 12 (x - 5)

e^{2 l n (2)}

\frac{1 ^{2} e ^{- 1}}{2 !}

8 b^{5} - 2 b^{4} - 10 b^{3}

What are the solutions to the equation (n+3)^2=0 ?
The solutions to the equation (n+3)^2=0 are n=-3
Find the zeros of (n+3)^2=0
The zeros of (n+3)^2=0 are n=-3