What are the solutions to the equation x^2-(3a+2b)x+6ab=0 ?

The solutions to the equation x^2-(3a+2b)x+6ab=0 are x=3a,x=2b

Find the zeros of x^2-(3a+2b)x+6ab=0

The zeros of x^2-(3a+2b)x+6ab=0 are x=3a,x=2b

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x^{2} - (3 a + 2 b) x + 6 ab = 0

x = 3 a, x = 2 b

Solution steps

x^{2} - (3 a + 2 b) x + 6 ab = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 a - 2 b ) \pm ( - 3 a - 2 b ) ^{2} - 4 \cdot 1 \cdot 6 ab}{2 \cdot 1}

Simplify

(- 3 a - 2 b)^{2} - 4 \cdot 1 \cdot 6 ab : 3 a - 2 b

x_{1, 2} = \frac{- ( - 3 a - 2 b ) \pm ( 3 a - 2 b )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 a - 2 b ) + 3 a - 2 b}{2 \cdot 1}, x_{2} = \frac{- ( - 3 a - 2 b ) - ( 3 a - 2 b )}{2 \cdot 1}

x = \frac{- ( - 3 a - 2 b ) + 3 a - 2 b}{2 \cdot 1} : 3 a

x = \frac{- ( - 3 a - 2 b ) - ( 3 a - 2 b )}{2 \cdot 1} : 2 b

The solutions to the quadratic equation are:

x = 3 a, x = 2 b

x^{2} - 8 x + 16 = 49

5 x^{2} - 10 x - 35 = 0

x^{2} - 28 = - 3 x

x, (x - 2)^{2} + (y - 3)^{2} + (z - 5)^{2} = 16

(3 x + 2) (x - 4) = 0

What are the solutions to the equation x^2-(3a+2b)x+6ab=0 ?
The solutions to the equation x^2-(3a+2b)x+6ab=0 are x=3a,x=2b
Find the zeros of x^2-(3a+2b)x+6ab=0
The zeros of x^2-(3a+2b)x+6ab=0 are x=3a,x=2b