What are the solutions to the equation solvefor x,9x^2-y^2-36x-6y+27=0 ?

The solutions to the equation solvefor x,9x^2-y^2-36x-6y+27=0 are x=(y+9)/3 ,x=(-y+3)/3

Find the zeros of solvefor x,9x^2-y^2-36x-6y+27=0

The zeros of solvefor x,9x^2-y^2-36x-6y+27=0 are x=(y+9)/3 ,x=(-y+3)/3

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solve for

x, 9 x^{2} - y^{2} - 36 x - 6 y + 27 = 0

x = \frac{y + 9}{3}, x = \frac{- y + 3}{3}

Solution steps

9 x^{2} - y^{2} - 36 x - 6 y + 27 = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 36 x - y^{2} - 6 y + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 9 ( - y ^{2} - 6 y + 27 )}{2 \cdot 9}

Simplify

(- 36)^{2} - 4 \cdot 9 (- y^{2} - 6 y + 27) : 6 (y + 3)

x_{1, 2} = \frac{- ( - 36 ) \pm 6 ( y + 3 )}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 6 ( y + 3 )}{2 \cdot 9}, x_{2} = \frac{- ( - 36 ) - 6 ( y + 3 )}{2 \cdot 9}

x = \frac{- ( - 36 ) + 6 ( y + 3 )}{2 \cdot 9} : \frac{y + 9}{3}

x = \frac{- ( - 36 ) - 6 ( y + 3 )}{2 \cdot 9} : \frac{- y + 3}{3}

The solutions to the quadratic equation are:

x = \frac{y + 9}{3}, x = \frac{- y + 3}{3}

4 x^{2} - 400 = 0

7^{2} + y^{2} = 2 5^{2}

(3 x - 1) (x + 2) - x (x - 4) = 0

40 = y^{2}

n^{2} - 5 n - 6 = 0

What are the solutions to the equation solvefor x,9x^2-y^2-36x-6y+27=0 ?
The solutions to the equation solvefor x,9x^2-y^2-36x-6y+27=0 are x=(y+9)/3 ,x=(-y+3)/3
Find the zeros of solvefor x,9x^2-y^2-36x-6y+27=0
The zeros of solvefor x,9x^2-y^2-36x-6y+27=0 are x=(y+9)/3 ,x=(-y+3)/3