What are the solutions to the equation 1.25x^2-25x+5=0 ?

The solutions to the equation 1.25x^2-25x+5=0 are x=2(5+2sqrt(6)),x=2(5-2sqrt(6))

Find the zeros of 1.25x^2-25x+5=0

The zeros of 1.25x^2-25x+5=0 are x=2(5+2sqrt(6)),x=2(5-2sqrt(6))

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1.25 x^{2} - 25 x + 5 = 0

x = 2 (5 + 26), x = 2 (5 - 26)

Decimal Notation

x = 19.79795 \dots, x = 0.20204 \dots

Solution steps

1.25 x^{2} - 25 x + 5 = 0

Multiply both sides by

100

125 x^{2} - 2500 x + 500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2500 ) \pm ( - 2500 ) ^{2} - 4 \cdot 125 \cdot 500}{2 \cdot 125}

(- 2500)^{2} - 4 \cdot 125 \cdot 500 = 10006

x_{1, 2} = \frac{- ( - 2500 ) \pm 1000 6}{2 \cdot 125}

Separate the solutions

x_{1} = \frac{- ( - 2500 ) + 1000 6}{2 \cdot 125}, x_{2} = \frac{- ( - 2500 ) - 1000 6}{2 \cdot 125}

x = \frac{- ( - 2500 ) + 1000 6}{2 \cdot 125} : 2 (5 + 26)

x = \frac{- ( - 2500 ) - 1000 6}{2 \cdot 125} : 2 (5 - 26)

The solutions to the quadratic equation are:

x = 2 (5 + 26), x = 2 (5 - 26)

4 x^{2} - x + 1 = x + 3 x^{2}

y^{2} = - 5

x, x^{2} = 9

36 x^{2} + 4 = 0

\frac{7 x ^{2} - 5 x}{3} = \frac{x ^{2} + 4 x}{6}

What are the solutions to the equation 1.25x^2-25x+5=0 ?
The solutions to the equation 1.25x^2-25x+5=0 are x=2(5+2sqrt(6)),x=2(5-2sqrt(6))
Find the zeros of 1.25x^2-25x+5=0
The zeros of 1.25x^2-25x+5=0 are x=2(5+2sqrt(6)),x=2(5-2sqrt(6))