What are the solutions to the equation (y+2)^2=16 ?

The solutions to the equation (y+2)^2=16 are y=2,y=-6

Find the zeros of (y+2)^2=16

The zeros of (y+2)^2=16 are y=2,y=-6

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(y + 2)^{2} = 16

y = 2, y = - 6

Solution steps

(y + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 2 = 16 : y = 2

Solve

y + 2 = - 16 : y = - 6

The solutions to the quadratic equation are:

y = 2, y = - 6

(x - 2) (x + 12) = 31

x^{2} - 8 x + 28 = 0

4^{2} + y^{2} = 4

4 x^{2} + 19 x = 5

5 x^{2} + 4 x + 20 = 0

What are the solutions to the equation (y+2)^2=16 ?
The solutions to the equation (y+2)^2=16 are y=2,y=-6
Find the zeros of (y+2)^2=16
The zeros of (y+2)^2=16 are y=2,y=-6