What are the solutions to the equation x^2+15x+141=-5x-7 ?

The solutions to the equation x^2+15x+141=-5x-7 are x=-10+4sqrt(3)i,x=-10-4sqrt(3)i

Find the zeros of x^2+15x+141=-5x-7

The zeros of x^2+15x+141=-5x-7 are x=-10+4sqrt(3)i,x=-10-4sqrt(3)i

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x^{2} + 15 x + 141 = - 5 x - 7

x = - 10 + 43 i, x = - 10 - 43 i

Solution steps

x^{2} + 15 x + 141 = - 5 x - 7

Move

7

to the left side

x^{2} + 15 x + 148 = - 5 x

Move

5 x

to the left side

x^{2} + 20 x + 148 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 148}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 148 : 83 i

x_{1, 2} = \frac{- 20 \pm 8 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 8 3 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 8 3 i}{2 \cdot 1}

x = \frac{- 20 + 8 3 i}{2 \cdot 1} : - 10 + 43 i

x = \frac{- 20 - 8 3 i}{2 \cdot 1} : - 10 - 43 i

The solutions to the quadratic equation are:

x = - 10 + 43 i, x = - 10 - 43 i

- 0.000003 x^{2} + 0.006 x = 0

5 x^{2} - 14 x + 8 = 0

170 - 108 x + 12 x^{2} = 0

x^{2} - 6 x + 9 = 7

y^{2} + 8 y = 0

What are the solutions to the equation x^2+15x+141=-5x-7 ?
The solutions to the equation x^2+15x+141=-5x-7 are x=-10+4sqrt(3)i,x=-10-4sqrt(3)i
Find the zeros of x^2+15x+141=-5x-7
The zeros of x^2+15x+141=-5x-7 are x=-10+4sqrt(3)i,x=-10-4sqrt(3)i