What are the solutions to the equation -8-3x+2x^2=3 ?

The solutions to the equation -8-3x+2x^2=3 are x=(3+sqrt(97))/4 ,x=(3-sqrt(97))/4

Find the zeros of -8-3x+2x^2=3

The zeros of -8-3x+2x^2=3 are x=(3+sqrt(97))/4 ,x=(3-sqrt(97))/4

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- 8 - 3 x + 2 x^{2} = 3

x = \frac{3 + 97}{4}, x = \frac{3 - 97}{4}

Decimal Notation

x = 3.21221 \dots, x = - 1.71221 \dots

Solution steps

- 8 - 3 x + 2 x^{2} = 3

Move

3

to the left side

2 x^{2} - 3 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 11) = 97

x_{1, 2} = \frac{- ( - 3 ) \pm 97}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 97}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 97}{2 \cdot 2}

x = \frac{- ( - 3 ) + 97}{2 \cdot 2} : \frac{3 + 97}{4}

x = \frac{- ( - 3 ) - 97}{2 \cdot 2} : \frac{3 - 97}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 97}{4}, x = \frac{3 - 97}{4}

3 x^{2} = 33

3 x^{2} = - 2

x, 2 x^{2} + 2 y^{2} - 2 x + 6 y + 5 = 0

(5 x - 4)^{2} - 1 = 35

- 3 x^{2} - x + 4 = 0

What are the solutions to the equation -8-3x+2x^2=3 ?
The solutions to the equation -8-3x+2x^2=3 are x=(3+sqrt(97))/4 ,x=(3-sqrt(97))/4
Find the zeros of -8-3x+2x^2=3
The zeros of -8-3x+2x^2=3 are x=(3+sqrt(97))/4 ,x=(3-sqrt(97))/4