What are the solutions to the equation 7x^2-12=0 ?

The solutions to the equation 7x^2-12=0 are x=(2sqrt(3))/(sqrt(7)),x=-(2sqrt(3))/(sqrt(7))

Find the zeros of 7x^2-12=0

The zeros of 7x^2-12=0 are x=(2sqrt(3))/(sqrt(7)),x=-(2sqrt(3))/(sqrt(7))

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7 x^{2} - 12 = 0

x = \frac{2 3}{7}, x = - \frac{2 3}{7}

Decimal Notation

x = 1.30930 \dots, x = - 1.30930 \dots

Solution steps

7 x^{2} - 12 = 0

Move

12

to the right side

7 x^{2} = 12

Divide both sides by

7

x^{2} = \frac{12}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{12}{7}, x = - \frac{12}{7}

\frac{12}{7} = \frac{2 3}{7}

- \frac{12}{7} = - \frac{2 3}{7}

x = \frac{2 3}{7}, x = - \frac{2 3}{7}

x, (x + y + 2 z)^{2} + (x + y - 2 z)^{2} = 8 (x + y) z

x^{2} = \frac{2}{3} (x + 1)

(x - 3)^{2} - 25 = 0

4 (a x^{2} - 5 x + 3) = 8 x^{2} + b x + 12

m^{2} + 2 m + 10 = 0

What are the solutions to the equation 7x^2-12=0 ?
The solutions to the equation 7x^2-12=0 are x=(2sqrt(3))/(sqrt(7)),x=-(2sqrt(3))/(sqrt(7))
Find the zeros of 7x^2-12=0
The zeros of 7x^2-12=0 are x=(2sqrt(3))/(sqrt(7)),x=-(2sqrt(3))/(sqrt(7))