What are the solutions to the equation 2x^2+10x+7=0 ?

The solutions to the equation 2x^2+10x+7=0 are x=(-5+sqrt(11))/2 ,x=-(5+sqrt(11))/2

Find the zeros of 2x^2+10x+7=0

The zeros of 2x^2+10x+7=0 are x=(-5+sqrt(11))/2 ,x=-(5+sqrt(11))/2

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2 x^{2} + 10 x + 7 = 0

x = \frac{- 5 + 11}{2}, x = - \frac{5 + 11}{2}

Decimal Notation

x = - 0.84168 \dots, x = - 4.15831 \dots

Solution steps

2 x^{2} + 10 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 7 = 211

x_{1, 2} = \frac{- 10 \pm 2 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2 11}{2 \cdot 2}, x_{2} = \frac{- 10 - 2 11}{2 \cdot 2}

x = \frac{- 10 + 2 11}{2 \cdot 2} : \frac{- 5 + 11}{2}

x = \frac{- 10 - 2 11}{2 \cdot 2} : - \frac{5 + 11}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 11}{2}, x = - \frac{5 + 11}{2}

x^{2} - 10 x + 16 = 0

1 8^{2} + 2 4^{2} = x^{2}

y, 2 x^{3} - 2 x y^{2} + 3 y^{2} - 14 = 0

2 (3 x - 2)^{2} + 10 = 42

(x - 4) (x - 6) = 8

What are the solutions to the equation 2x^2+10x+7=0 ?
The solutions to the equation 2x^2+10x+7=0 are x=(-5+sqrt(11))/2 ,x=-(5+sqrt(11))/2
Find the zeros of 2x^2+10x+7=0
The zeros of 2x^2+10x+7=0 are x=(-5+sqrt(11))/2 ,x=-(5+sqrt(11))/2