What are the solutions to the equation k(4k+1)=0 ?

The solutions to the equation k(4k+1)=0 are k=0,k=-1/4

Find the zeros of k(4k+1)=0

The zeros of k(4k+1)=0 are k=0,k=-1/4

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k (4 k + 1) = 0

k = 0, k = - \frac{1}{4}

Decimal Notation

k = 0, k = - 0.25

Solution steps

k (4 k + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

k = 0 or 4 k + 1 = 0

Solve

4 k + 1 = 0 : k = - \frac{1}{4}

The solutions to the quadratic equation are:

k = 0, k = - \frac{1}{4}

16 p + 37 = 49 - 21 p

8 x + 4 = 6 x + 6

\frac{0}{- 3}

3 (- \frac{4}{5})^{0}

- 16 + 5 x = - 71

What are the solutions to the equation k(4k+1)=0 ?
The solutions to the equation k(4k+1)=0 are k=0,k=-1/4
Find the zeros of k(4k+1)=0
The zeros of k(4k+1)=0 are k=0,k=-1/4