What are the solutions to the equation x^2+4x-25=0 ?

The solutions to the equation x^2+4x-25=0 are x=-2+sqrt(29),x=-2-sqrt(29)

Find the zeros of x^2+4x-25=0

The zeros of x^2+4x-25=0 are x=-2+sqrt(29),x=-2-sqrt(29)

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x^{2} + 4 x - 25 = 0

x = - 2 + 29, x = - 2 - 29

Decimal Notation

x = 3.38516 \dots, x = - 7.38516 \dots

Solution steps

x^{2} + 4 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 25) = 229

x_{1, 2} = \frac{- 4 \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 29}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 29}{2 \cdot 1}

x = \frac{- 4 + 2 29}{2 \cdot 1} : - 2 + 29

x = \frac{- 4 - 2 29}{2 \cdot 1} : - 2 - 29

The solutions to the quadratic equation are:

x = - 2 + 29, x = - 2 - 29

- 3 t^{2} + 14 t - 14 = 0

9 b^{2} = 25

12 x^{2} - 13 x - 4 = 0

x^{2} + 2 x - 24 = 0

5 x^{2} + 27 x - 18 = 0

What are the solutions to the equation x^2+4x-25=0 ?
The solutions to the equation x^2+4x-25=0 are x=-2+sqrt(29),x=-2-sqrt(29)
Find the zeros of x^2+4x-25=0
The zeros of x^2+4x-25=0 are x=-2+sqrt(29),x=-2-sqrt(29)