What are the solutions to the equation 6x^2-9x+1=x ?

The solutions to the equation 6x^2-9x+1=x are x=(5+sqrt(19))/6 ,x=(5-sqrt(19))/6

Find the zeros of 6x^2-9x+1=x

The zeros of 6x^2-9x+1=x are x=(5+sqrt(19))/6 ,x=(5-sqrt(19))/6

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6 x^{2} - 9 x + 1 = x

x = \frac{5 + 19}{6}, x = \frac{5 - 19}{6}

Decimal Notation

x = 1.55981 \dots, x = 0.10685 \dots

Solution steps

6 x^{2} - 9 x + 1 = x

Move

x

to the left side

6 x^{2} - 10 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

(- 10)^{2} - 4 \cdot 6 \cdot 1 = 219

x_{1, 2} = \frac{- ( - 10 ) \pm 2 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 19}{2 \cdot 6}, x_{2} = \frac{- ( - 10 ) - 2 19}{2 \cdot 6}

x = \frac{- ( - 10 ) + 2 19}{2 \cdot 6} : \frac{5 + 19}{6}

x = \frac{- ( - 10 ) - 2 19}{2 \cdot 6} : \frac{5 - 19}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 19}{6}, x = \frac{5 - 19}{6}

2 (x - 9)^{2} + 8 = 0

x, x^{2} y = 1

(2 x + 5)^{2} = 60

x^{2} + 28 = 11 x

x^{2} - 26 x + 144 = 0

What are the solutions to the equation 6x^2-9x+1=x ?
The solutions to the equation 6x^2-9x+1=x are x=(5+sqrt(19))/6 ,x=(5-sqrt(19))/6
Find the zeros of 6x^2-9x+1=x
The zeros of 6x^2-9x+1=x are x=(5+sqrt(19))/6 ,x=(5-sqrt(19))/6