What are the solutions to the equation u^2-7u+10=0 ?

The solutions to the equation u^2-7u+10=0 are u=5,u=2

Find the zeros of u^2-7u+10=0

The zeros of u^2-7u+10=0 are u=5,u=2

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u^{2} - 7 u + 10 = 0

u = 5, u = 2

Solution steps

u^{2} - 7 u + 10 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

u_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, u_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

u = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

u = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

u = 5, u = 2

0 = 2 x^{2} - 5 x - 3

s, v = \frac{1}{3} s^{2} h

7 x^{2} - 2 x = 1

15 - 2 x = 3 x^{2}

x^{2} + 3 x = - 4

What are the solutions to the equation u^2-7u+10=0 ?
The solutions to the equation u^2-7u+10=0 are u=5,u=2
Find the zeros of u^2-7u+10=0
The zeros of u^2-7u+10=0 are u=5,u=2