What are the solutions to the equation completesquare x^2-x+7 ?

The solutions to the equation completesquare x^2-x+7 are (x-1/2)^2+27/4

Find the zeros of completesquare x^2-x+7

The zeros of completesquare x^2-x+7 are (x-1/2)^2+27/4

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complete the square

x^{2} - x + 7

(x - \frac{1}{2})^{2} + \frac{27}{4}

Solution steps

x^{2} - x + 7

Write

x^{2} - x + 7

in the form:

x^{2} + 2 a x + a^{2}

2 a = - 1 : a = - \frac{1}{2}

Add and subtract

(- \frac{1}{2})^{2}

x^{2} - x + 7 + (- \frac{1}{2})^{2} - (- \frac{1}{2})^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 1 x + (- \frac{1}{2})^{2} = (x - \frac{1}{2})^{2}

(x - \frac{1}{2})^{2} + 7 - (- \frac{1}{2})^{2}

Simplify

(x - \frac{1}{2})^{2} + \frac{27}{4}

x^{2} - x + 9

x^{2} - x - 2

h, (x - h)^{2} + (y - k)^{2} = r^{2}

x^{2} - 14 x + 33 = 0

64 x^{2} = 25

What are the solutions to the equation completesquare x^2-x+7 ?
The solutions to the equation completesquare x^2-x+7 are (x-1/2)^2+27/4
Find the zeros of completesquare x^2-x+7
The zeros of completesquare x^2-x+7 are (x-1/2)^2+27/4