What are the solutions to the equation x^2+x=-3 ?

The solutions to the equation x^2+x=-3 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

Find the zeros of x^2+x=-3

The zeros of x^2+x=-3 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + x = - 3

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

Solution steps

x^{2} + x = - 3

Move

3

to the left side

x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 3 : 11 i

x_{1, 2} = \frac{- 1 \pm 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 11 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 11 i}{2 \cdot 1}

x = \frac{- 1 + 11 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{11}{2}

x = \frac{- 1 - 11 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

x, f = (3 m - 1) x^{2} - m x + m

20 x^{2} + 3920 = 0

x^{2} - 10 x - 50 = 0

7 (x - 4)^{2} - 3 (x + 5) = 4 (x + 1) (x - 1) - 2

\frac{1}{2} x^{2} + x + \frac{1}{2} = 0

What are the solutions to the equation x^2+x=-3 ?
The solutions to the equation x^2+x=-3 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2
Find the zeros of x^2+x=-3
The zeros of x^2+x=-3 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2