What are the solutions to the equation 2x^2+12x+14=0 ?

The solutions to the equation 2x^2+12x+14=0 are x=-3+sqrt(2),x=-3-sqrt(2)

Find the zeros of 2x^2+12x+14=0

The zeros of 2x^2+12x+14=0 are x=-3+sqrt(2),x=-3-sqrt(2)

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2 x^{2} + 12 x + 14 = 0

x = - 3 + 2, x = - 3 - 2

Decimal Notation

x = - 1.58578 \dots, x = - 4.41421 \dots

Solution steps

2 x^{2} + 12 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 14 = 42

x_{1, 2} = \frac{- 12 \pm 4 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 2}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 2}{2 \cdot 2}

x = \frac{- 12 + 4 2}{2 \cdot 2} : - 3 + 2

x = \frac{- 12 - 4 2}{2 \cdot 2} : - 3 - 2

The solutions to the quadratic equation are:

x = - 3 + 2, x = - 3 - 2

(2 x - 5) (x + 7) = 0

x^{2} + 1 = 3

x, x^{2} y + x^{2} - x y^{2} + x y + 2 x = 0

x^{2} - 6 x + 15 = 6

x^{2} - 14 x + 40 = 0

What are the solutions to the equation 2x^2+12x+14=0 ?
The solutions to the equation 2x^2+12x+14=0 are x=-3+sqrt(2),x=-3-sqrt(2)
Find the zeros of 2x^2+12x+14=0
The zeros of 2x^2+12x+14=0 are x=-3+sqrt(2),x=-3-sqrt(2)