What are the solutions to the equation 3x^2+42x=-24 ?

The solutions to the equation 3x^2+42x=-24 are x=-7+sqrt(41),x=-7-sqrt(41)

Find the zeros of 3x^2+42x=-24

The zeros of 3x^2+42x=-24 are x=-7+sqrt(41),x=-7-sqrt(41)

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3 x^{2} + 42 x = - 24

x = - 7 + 41, x = - 7 - 41

Decimal Notation

x = - 0.59687 \dots, x = - 13.40312 \dots

Solution steps

3 x^{2} + 42 x = - 24

Move

24

to the left side

3 x^{2} + 42 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

4 2^{2} - 4 \cdot 3 \cdot 24 = 641

x_{1, 2} = \frac{- 42 \pm 6 41}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 42 + 6 41}{2 \cdot 3}, x_{2} = \frac{- 42 - 6 41}{2 \cdot 3}

x = \frac{- 42 + 6 41}{2 \cdot 3} : - 7 + 41

x = \frac{- 42 - 6 41}{2 \cdot 3} : - 7 - 41

The solutions to the quadratic equation are:

x = - 7 + 41, x = - 7 - 41

9 - x^{2} = x^{2} + 1

7 x^{2} - 9 x + 12 = 5 x^{2} - 6

1 2^{2} = 6^{2} + x^{2}

r^{2} - 10 = 3 r

- x^{2} + 6 x = (x + 3) 2 - 9

What are the solutions to the equation 3x^2+42x=-24 ?
The solutions to the equation 3x^2+42x=-24 are x=-7+sqrt(41),x=-7-sqrt(41)
Find the zeros of 3x^2+42x=-24
The zeros of 3x^2+42x=-24 are x=-7+sqrt(41),x=-7-sqrt(41)