What are the solutions to the equation y^2+6y-1=0 ?

The solutions to the equation y^2+6y-1=0 are y=-3+sqrt(10),y=-3-sqrt(10)

Find the zeros of y^2+6y-1=0

The zeros of y^2+6y-1=0 are y=-3+sqrt(10),y=-3-sqrt(10)

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y^{2} + 6 y - 1 = 0

y = - 3 + 10, y = - 3 - 10

Decimal Notation

y = 0.16227 \dots, y = - 6.16227 \dots

Solution steps

y^{2} + 6 y - 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 1) = 210

y_{1, 2} = \frac{- 6 \pm 2 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 2 10}{2 \cdot 1}, y_{2} = \frac{- 6 - 2 10}{2 \cdot 1}

y = \frac{- 6 + 2 10}{2 \cdot 1} : - 3 + 10

y = \frac{- 6 - 2 10}{2 \cdot 1} : - 3 - 10

The solutions to the quadratic equation are:

y = - 3 + 10, y = - 3 - 10

2 x^{2} - 2 x + 8 = 0

x, y^{2} (x^{2} - 4) = x + 2

x^{2} + 4 = 20

2 x^{2} - 3 x - 5 = - 10 x

x^{2} - 2 x + 17

What are the solutions to the equation y^2+6y-1=0 ?
The solutions to the equation y^2+6y-1=0 are y=-3+sqrt(10),y=-3-sqrt(10)
Find the zeros of y^2+6y-1=0
The zeros of y^2+6y-1=0 are y=-3+sqrt(10),y=-3-sqrt(10)