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Popular >

16x^2+8x+1>0

Solution

16 x^{2} + 8 x + 1 > 0

Solution

x < - \frac{1}{4} or x > - \frac{1}{4}

+2

Interval Notation

(- \infty, - \frac{1}{4}) \cup (- \frac{1}{4}, \infty)

Decimal Notation

x < - 0.25 or x > - 0.25

Solution steps

16 x^{2} + 8 x + 1 > 0

Factor

16 x^{2} + 8 x + 1 : (4 x + 1)^{2}

(4 x + 1)^{2} > 0

For

u^{n} > 0

, if

n

is even then

u < 0

or

u > 0

4 x + 1 < 0 or 4 x + 1 > 0

4 x + 1 < 0 : x < - \frac{1}{4}

4 x + 1 > 0 : x > - \frac{1}{4}

Combine the intervals

x < - \frac{1}{4} or x > - \frac{1}{4}

Popular Examples

(x-2)/(4x+7)<= 4

\frac{x - 2}{4 x + 7} \leq 4

simplify ((a^4)/(-2b^2))^4 simplify

(\frac{a ^{4}}{- 2 b ^{2}})^{4}

simplify 5/(10n^2+16n+6)+(n-6)/(10n^2+16n+6)simplify

\frac{5}{10 n ^{2} + 16 n + 6} + \frac{n - 6}{10 n ^{2} + 16 n + 6}

(x - 5) (2 x + 7) = 0

factor 10t(t-2)+11(t-2)factor

10 t (t - 2) + 11 (t - 2)

Frequently Asked Questions (FAQ)

What is 16x^2+8x+1>0 ?
The solution to 16x^2+8x+1>0 is x<-1/4 \lor x>-1/4