What are the solutions to the equation λ^2+5λ+6=0 ?

The solutions to the equation λ^2+5λ+6=0 are λ=-2,λ=-3

Find the zeros of λ^2+5λ+6=0

The zeros of λ^2+5λ+6=0 are λ=-2,λ=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

λ^{2} + 5 λ + 6 = 0

λ = - 2, λ = - 3

Solution steps

λ^{2} + 5 λ + 6 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

λ_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- 5 + 1}{2 \cdot 1}, λ_{2} = \frac{- 5 - 1}{2 \cdot 1}

λ = \frac{- 5 + 1}{2 \cdot 1} : - 2

λ = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

λ = - 2, λ = - 3

3 x^{2} - 4 x - 55 = 0

5 x^{2} - 45 x = 0

x^{2} + 3 x = 7

y^{2} - 9 y

x, (y - 1)^{3} = x^{2}

What are the solutions to the equation λ^2+5λ+6=0 ?
The solutions to the equation λ^2+5λ+6=0 are λ=-2,λ=-3
Find the zeros of λ^2+5λ+6=0
The zeros of λ^2+5λ+6=0 are λ=-2,λ=-3