What are the solutions to the equation 7x^2-2x-9=0 ?

The solutions to the equation 7x^2-2x-9=0 are x= 9/7 ,x=-1

Find the zeros of 7x^2-2x-9=0

The zeros of 7x^2-2x-9=0 are x= 9/7 ,x=-1

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7 x^{2} - 2 x - 9 = 0

x = \frac{9}{7}, x = - 1

Decimal Notation

x = 1.28571 \dots, x = - 1

Solution steps

7 x^{2} - 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 9 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 9) = 16

x_{1, 2} = \frac{- ( - 2 ) \pm 16}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 16}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 16}{2 \cdot 7}

x = \frac{- ( - 2 ) + 16}{2 \cdot 7} : \frac{9}{7}

x = \frac{- ( - 2 ) - 16}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = \frac{9}{7}, x = - 1

a^{2} = 32

a^{2} = 49

x^{2} - 6 x + 2 = 0

X, Y = (2 X + 1) (X 3 + 5)

2 x^{2} + 16 x - 3

What are the solutions to the equation 7x^2-2x-9=0 ?
The solutions to the equation 7x^2-2x-9=0 are x= 9/7 ,x=-1
Find the zeros of 7x^2-2x-9=0
The zeros of 7x^2-2x-9=0 are x= 9/7 ,x=-1