What are the solutions to the equation solvefor x,x^2-x=0 ?

The solutions to the equation solvefor x,x^2-x=0 are x=1,x=0

Find the zeros of solvefor x,x^2-x=0

The zeros of solvefor x,x^2-x=0 are x=1,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x, x^{2} - x = 0

x = 1, x = 0

Solution steps

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

6 x^{2} + 2 x + 6 = 0

x^{2} - 12 x + 11 = 0

25 \cdot 1 0^{- 9} s^{2} + 0.35 \cdot 1 0^{- 3} s + 1 = 0

4 - 4 x + x^{2} = 0

7 x^{2} + 10 = 0

What are the solutions to the equation solvefor x,x^2-x=0 ?
The solutions to the equation solvefor x,x^2-x=0 are x=1,x=0
Find the zeros of solvefor x,x^2-x=0
The zeros of solvefor x,x^2-x=0 are x=1,x=0