What are the solutions to the equation 24^2+32^2=c^2 ?

The solutions to the equation 24^2+32^2=c^2 are c=40,c=-40

Find the zeros of 24^2+32^2=c^2

The zeros of 24^2+32^2=c^2 are c=40,c=-40

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2 4^{2} + 3 2^{2} = c^{2}

c = 40, c = - 40

Solution steps

2 4^{2} + 3 2^{2} = c^{2}

Switch sides

c^{2} = 2 4^{2} + 3 2^{2}

Simplify

2 4^{2} + 3 2^{2} : 1600

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 1600, c = - 1600

1600 = 40

- 1600 = - 40

c = 40, c = - 40

2 x^{2} - 9 x - 32 = 0

- x^{2} = x^{2}

t^{2} + 6 t + 9 = 0

x^{2} + 4 x - 3 = - 4 - 2 x

9 x^{2} + 12 x = 0

What are the solutions to the equation 24^2+32^2=c^2 ?
The solutions to the equation 24^2+32^2=c^2 are c=40,c=-40
Find the zeros of 24^2+32^2=c^2
The zeros of 24^2+32^2=c^2 are c=40,c=-40