What are the solutions to the equation 3n^2+24n=-48 ?

The solutions to the equation 3n^2+24n=-48 are n=-4

Find the zeros of 3n^2+24n=-48

The zeros of 3n^2+24n=-48 are n=-4

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3 n^{2} + 24 n = - 48

n = - 4

Solution steps

3 n^{2} + 24 n = - 48

Move

48

to the left side

3 n^{2} + 24 n + 48 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 48}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 48 = 0

n_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 3}

n = \frac{- 24}{2 \cdot 3}

\frac{- 24}{2 \cdot 3} = - 4

n = - 4

The solution to the quadratic equation is:

n = - 4

4 x^{2} + 4 (k - 2) x + k = 0

x^{2} + x = x + 3

4 x^{2} - 5 = 7 x

x^{2} + 5 a x + 6 a^{2} = 0

x^{2} + 2 x - 30 = 0

What are the solutions to the equation 3n^2+24n=-48 ?
The solutions to the equation 3n^2+24n=-48 are n=-4
Find the zeros of 3n^2+24n=-48
The zeros of 3n^2+24n=-48 are n=-4