What are the solutions to the equation solvefor x,f=x^2-6x+m-3 ?

The solutions to the equation solvefor x,f=x^2-6x+m-3 are x=3+sqrt(f+12-m),x=3-sqrt(f+12-m)

Find the zeros of solvefor x,f=x^2-6x+m-3

The zeros of solvefor x,f=x^2-6x+m-3 are x=3+sqrt(f+12-m),x=3-sqrt(f+12-m)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, f = x^{2} - 6 x + m - 3

x = 3 + f + 12 - m, x = 3 - f + 12 - m

Solution steps

f = x^{2} - 6 x + m - 3

Switch sides

x^{2} - 6 x + m - 3 = f

Move

f

to the left side

x^{2} - 6 x + m - 3 - f = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( m - 3 - f )}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot (m - 3 - f) : 2 f + 12 - m

x_{1, 2} = \frac{- ( - 6 ) \pm 2 f + 12 - m}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 f + 12 - m}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 f + 12 - m}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 f + 12 - m}{2 \cdot 1} : 3 + f + 12 - m

x = \frac{- ( - 6 ) - 2 f + 12 - m}{2 \cdot 1} : 3 - f + 12 - m

The solutions to the quadratic equation are:

x = 3 + f + 12 - m, x = 3 - f + 12 - m

x^{2} + x = \frac{19}{4}

2 x (x - 2) + 2 = 5 - 3 x

y^{2} - 3 y - 10 = 0

x^{2} + 10 + 21 = 0

x, x^{2} - 45 m x + 15 m^{2} = 0

What are the solutions to the equation solvefor x,f=x^2-6x+m-3 ?
The solutions to the equation solvefor x,f=x^2-6x+m-3 are x=3+sqrt(f+12-m),x=3-sqrt(f+12-m)
Find the zeros of solvefor x,f=x^2-6x+m-3
The zeros of solvefor x,f=x^2-6x+m-3 are x=3+sqrt(f+12-m),x=3-sqrt(f+12-m)