What are the solutions to the equation y^2-7y-3=0 ?

The solutions to the equation y^2-7y-3=0 are y=(7+sqrt(61))/2 ,y=(7-sqrt(61))/2

Find the zeros of y^2-7y-3=0

The zeros of y^2-7y-3=0 are y=(7+sqrt(61))/2 ,y=(7-sqrt(61))/2

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y^{2} - 7 y - 3 = 0

y = \frac{7 + 61}{2}, y = \frac{7 - 61}{2}

Decimal Notation

y = 7.40512 \dots, y = - 0.40512 \dots

Solution steps

y^{2} - 7 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 3) = 61

y_{1, 2} = \frac{- ( - 7 ) \pm 61}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 61}{2 \cdot 1}, y_{2} = \frac{- ( - 7 ) - 61}{2 \cdot 1}

y = \frac{- ( - 7 ) + 61}{2 \cdot 1} : \frac{7 + 61}{2}

y = \frac{- ( - 7 ) - 61}{2 \cdot 1} : \frac{7 - 61}{2}

The solutions to the quadratic equation are:

y = \frac{7 + 61}{2}, y = \frac{7 - 61}{2}

x^{2} + 8 = 80

15 x - 10 = 6 x (x + 2) + (- x + 3)

n^{2} = 3 n + 40

8 m - m^{2} = 14

5 (1 - x) 2 - 6 (x^{2} - 3 x - 7) = x (x - 3) - 2 x (x + 5) - 2

What are the solutions to the equation y^2-7y-3=0 ?
The solutions to the equation y^2-7y-3=0 are y=(7+sqrt(61))/2 ,y=(7-sqrt(61))/2
Find the zeros of y^2-7y-3=0
The zeros of y^2-7y-3=0 are y=(7+sqrt(61))/2 ,y=(7-sqrt(61))/2