What are the solutions to the equation 4x^2=196 ?

The solutions to the equation 4x^2=196 are x=7,x=-7

Find the zeros of 4x^2=196

The zeros of 4x^2=196 are x=7,x=-7

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4 x^{2} = 196

x = 7, x = - 7

Solution steps

4 x^{2} = 196

Divide both sides by

4

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

b^{2} - 6 b + 9 = 0

x^{2} + 11 = 24

x (x - 2) + 4 x = 8

x^{2} - 1 = x + 5

x = x^{2} - x

What are the solutions to the equation 4x^2=196 ?
The solutions to the equation 4x^2=196 are x=7,x=-7
Find the zeros of 4x^2=196
The zeros of 4x^2=196 are x=7,x=-7