What are the solutions to the equation 0=96t-16t^2 ?

The solutions to the equation 0=96t-16t^2 are t=0,t=6

Find the zeros of 0=96t-16t^2

The zeros of 0=96t-16t^2 are t=0,t=6

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0 = 96 t - 16 t^{2}

t = 0, t = 6

Solution steps

0 = 96 t - 16 t^{2}

Switch sides

96 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 96 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 0 = 96

t_{1, 2} = \frac{- 96 \pm 96}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 96}{2 ( - 16 )}, t_{2} = \frac{- 96 - 96}{2 ( - 16 )}

t = \frac{- 96 + 96}{2 ( - 16 )} : 0

t = \frac{- 96 - 96}{2 ( - 16 )} : 6

The solutions to the quadratic equation are:

t = 0, t = 6

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What are the solutions to the equation 0=96t-16t^2 ?
The solutions to the equation 0=96t-16t^2 are t=0,t=6
Find the zeros of 0=96t-16t^2
The zeros of 0=96t-16t^2 are t=0,t=6