What are the solutions to the equation 12x^2+11x-5=0 ?

The solutions to the equation 12x^2+11x-5=0 are x= 1/3 ,x=-5/4

Find the zeros of 12x^2+11x-5=0

The zeros of 12x^2+11x-5=0 are x= 1/3 ,x=-5/4

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12 x^{2} + 11 x - 5 = 0

x = \frac{1}{3}, x = - \frac{5}{4}

Decimal Notation

x = 0.33333 \dots, x = - 1.25

Solution steps

12 x^{2} + 11 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

1 1^{2} - 4 \cdot 12 (- 5) = 19

x_{1, 2} = \frac{- 11 \pm 19}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 11 + 19}{2 \cdot 12}, x_{2} = \frac{- 11 - 19}{2 \cdot 12}

x = \frac{- 11 + 19}{2 \cdot 12} : \frac{1}{3}

x = \frac{- 11 - 19}{2 \cdot 12} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{5}{4}

x, 3 x^{2} - 1 = 0

5 x^{2} + 5 x - 360 = 0

4 x^{2} - 16 - 12 x = 0

x, 3 x^{2} - 3 = 0

5.1 z^{2} - 4.6 z - 2.1 = 0

What are the solutions to the equation 12x^2+11x-5=0 ?
The solutions to the equation 12x^2+11x-5=0 are x= 1/3 ,x=-5/4
Find the zeros of 12x^2+11x-5=0
The zeros of 12x^2+11x-5=0 are x= 1/3 ,x=-5/4