What are the solutions to the equation 3x^2+16x-84=0 ?

The solutions to the equation 3x^2+16x-84=0 are x=(2(sqrt(79)-4))/3 ,x=-(2(4+sqrt(79)))/3

Find the zeros of 3x^2+16x-84=0

The zeros of 3x^2+16x-84=0 are x=(2(sqrt(79)-4))/3 ,x=-(2(4+sqrt(79)))/3

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3 x^{2} + 16 x - 84 = 0

x = \frac{2 ( 79 - 4 )}{3}, x = - \frac{2 ( 4 + 79 )}{3}

Decimal Notation

x = 3.25879 \dots, x = - 8.59212 \dots

Solution steps

3 x^{2} + 16 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 ( - 84 )}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 (- 84) = 479

x_{1, 2} = \frac{- 16 \pm 4 79}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 16 + 4 79}{2 \cdot 3}, x_{2} = \frac{- 16 - 4 79}{2 \cdot 3}

x = \frac{- 16 + 4 79}{2 \cdot 3} : \frac{2 ( 79 - 4 )}{3}

x = \frac{- 16 - 4 79}{2 \cdot 3} : - \frac{2 ( 4 + 79 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 79 - 4 )}{3}, x = - \frac{2 ( 4 + 79 )}{3}

4 x^{2} + 12 x - 8 = 0

- 9 b^{2} = - 8 b + 8

x^{2} + 30 = 11 x

9 x^{2} - 48 x + 65 = 0

- x^{2} + x - 4 = 0

What are the solutions to the equation 3x^2+16x-84=0 ?
The solutions to the equation 3x^2+16x-84=0 are x=(2(sqrt(79)-4))/3 ,x=-(2(4+sqrt(79)))/3
Find the zeros of 3x^2+16x-84=0
The zeros of 3x^2+16x-84=0 are x=(2(sqrt(79)-4))/3 ,x=-(2(4+sqrt(79)))/3