What are the solutions to the equation m^2+8m+12=0 ?

The solutions to the equation m^2+8m+12=0 are m=-2,m=-6

Find the zeros of m^2+8m+12=0

The zeros of m^2+8m+12=0 are m=-2,m=-6

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m^{2} + 8 m + 12 = 0

m = - 2, m = - 6

Solution steps

m^{2} + 8 m + 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

m_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 4}{2 \cdot 1}, m_{2} = \frac{- 8 - 4}{2 \cdot 1}

m = \frac{- 8 + 4}{2 \cdot 1} : - 2

m = \frac{- 8 - 4}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

m = - 2, m = - 6

3 x^{2} - 6 x + 4

- 3 x^{2} + 30 x - 75 = 0

x^{2} = 4 x - 15

x, x^{2} + m^{2} x (m - 2) = 2 m^{5}

x, x^{2} + 5 x y + 8 y^{2} - 10 x + 3 y + 10 = 0

What are the solutions to the equation m^2+8m+12=0 ?
The solutions to the equation m^2+8m+12=0 are m=-2,m=-6
Find the zeros of m^2+8m+12=0
The zeros of m^2+8m+12=0 are m=-2,m=-6