What are the solutions to the equation -2x^2+16=0 ?

The solutions to the equation -2x^2+16=0 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of -2x^2+16=0

The zeros of -2x^2+16=0 are x=2sqrt(2),x=-2sqrt(2)

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- 2 x^{2} + 16 = 0

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

- 2 x^{2} + 16 = 0

Move

16

to the right side

- 2 x^{2} = - 16

Divide both sides by

- 2

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

x^{2} + 6 x + 4 = 0

x^{2} + 2 = 6 x - 6

2 x^{2} + 2 x - 6 = c_{1} (x^{2} - 1) + c_{2} (x^{2} - x + 1)

5 x - 6 = x^{2}

t^{2} + 3 t - 4 = 0

What are the solutions to the equation -2x^2+16=0 ?
The solutions to the equation -2x^2+16=0 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of -2x^2+16=0
The zeros of -2x^2+16=0 are x=2sqrt(2),x=-2sqrt(2)