What are the solutions to the equation solvefor x,x^2-4x+4=0 ?

The solutions to the equation solvefor x,x^2-4x+4=0 are x=2

Find the zeros of solvefor x,x^2-4x+4=0

The zeros of solvefor x,x^2-4x+4=0 are x=2

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x, x^{2} - 4 x + 4 = 0

x = 2

Solution steps

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

x^{2} - 6 x - 7

x^{2} - 32 x + 4 = 0

5 = 4 n^{2} + n + 5

2 x^{2} + x + 10 = 5 - 4 x - x^{2}

182 - 27 x + x^{2} = 0

What are the solutions to the equation solvefor x,x^2-4x+4=0 ?
The solutions to the equation solvefor x,x^2-4x+4=0 are x=2
Find the zeros of solvefor x,x^2-4x+4=0
The zeros of solvefor x,x^2-4x+4=0 are x=2