What are the solutions to the equation u^2-4u-9=0 ?

The solutions to the equation u^2-4u-9=0 are u=2+sqrt(13),u=2-sqrt(13)

Find the zeros of u^2-4u-9=0

The zeros of u^2-4u-9=0 are u=2+sqrt(13),u=2-sqrt(13)

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u^{2} - 4 u - 9 = 0

u = 2 + 13, u = 2 - 13

Decimal

u = 5.60555 \dots, u = - 1.60555 \dots

Solution steps

u^{2} - 4 u - 9 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 9) = 213

u_{1, 2} = \frac{- ( - 4 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 4 ) + 2 13}{2 \cdot 1}, u_{2} = \frac{- ( - 4 ) - 2 13}{2 \cdot 1}

u = \frac{- ( - 4 ) + 2 13}{2 \cdot 1} : 2 + 13

u = \frac{- ( - 4 ) - 2 13}{2 \cdot 1} : 2 - 13

The solutions to the quadratic equation are:

u = 2 + 13, u = 2 - 13

u^{2} = 9

- 16 t^{2} + 40 = 40 (t)

(x + 5)^{2} - 18 = 63

x, 52 x^{2} + 72 x y + 73 y^{2} - 40 x + 30 y = 75

2 z^{2} - 3 z + 3 = 0

What are the solutions to the equation u^2-4u-9=0 ?
The solutions to the equation u^2-4u-9=0 are u=2+sqrt(13),u=2-sqrt(13)
Find the zeros of u^2-4u-9=0
The zeros of u^2-4u-9=0 are u=2+sqrt(13),u=2-sqrt(13)