What are the solutions to the equation r^2+3r+r=0 ?

The solutions to the equation r^2+3r+r=0 are r=0,r=-4

Find the zeros of r^2+3r+r=0

The zeros of r^2+3r+r=0 are r=0,r=-4

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r^{2} + 3 r + r = 0

r = 0, r = - 4

Solution steps

r^{2} + 3 r + r = 0

Refine

r^{2} + 4 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

r_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 4 + 4}{2 \cdot 1}, r_{2} = \frac{- 4 - 4}{2 \cdot 1}

r = \frac{- 4 + 4}{2 \cdot 1} : 0

r = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

r = 0, r = - 4

x^{2} + 5 x = 0

x, y x^{2} - x^{2} - 4 y = 0

y^{2} - 8 = 0

(x - 6) (x - 2) = 0

\frac{2 x ^{2} - 1}{2} - \frac{x - 1}{3} = \frac{1 - x}{6}

What are the solutions to the equation r^2+3r+r=0 ?
The solutions to the equation r^2+3r+r=0 are r=0,r=-4
Find the zeros of r^2+3r+r=0
The zeros of r^2+3r+r=0 are r=0,r=-4