What are the solutions to the equation x^2+4x-221=0 ?

The solutions to the equation x^2+4x-221=0 are x=13,x=-17

Find the zeros of x^2+4x-221=0

The zeros of x^2+4x-221=0 are x=13,x=-17

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x^{2} + 4 x - 221 = 0

x = 13, x = - 17

Solution steps

x^{2} + 4 x - 221 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 221 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 221) = 30

x_{1, 2} = \frac{- 4 \pm 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 30}{2 \cdot 1}, x_{2} = \frac{- 4 - 30}{2 \cdot 1}

x = \frac{- 4 + 30}{2 \cdot 1} : 13

x = \frac{- 4 - 30}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = 13, x = - 17

10 x^{2} + 19 x + 6 = (5 x + a) (b x + c)

- 4 x^{2} + 8 x - 4 = 0

1 - 1.2 z + 0.85 \cdot z^{2} = 0

15 + 2 x^{2} = 177

- 3 x^{2} - 4 = 0

What are the solutions to the equation x^2+4x-221=0 ?
The solutions to the equation x^2+4x-221=0 are x=13,x=-17
Find the zeros of x^2+4x-221=0
The zeros of x^2+4x-221=0 are x=13,x=-17