What are the solutions to the equation solvefor x,f=-4(x+h)^2-k ?

The solutions to the equation solvefor x,f=-4(x+h)^2-k are x=(isqrt(f+k))/2-h,x=-(isqrt(f+k))/2-h

Find the zeros of solvefor x,f=-4(x+h)^2-k

The zeros of solvefor x,f=-4(x+h)^2-k are x=(isqrt(f+k))/2-h,x=-(isqrt(f+k))/2-h

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solve for

x, f = - 4 (x + h)^{2} - k

x = \frac{i f + k}{2} - h, x = - \frac{i f + k}{2} - h

Solution steps

f = - 4 (x + h)^{2} - k

Switch sides

- 4 (x + h)^{2} - k = f

Move

k

to the right side

- 4 (x + h)^{2} = f + k

Divide both sides by

- 4

(x + h)^{2} = - \frac{f + k}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + h = - \frac{f + k}{4} : x = \frac{i f + k}{2} - h

Solve

x + h = - - \frac{f + k}{4} : x = - \frac{i f + k}{2} - h

The solutions to the quadratic equation are:

x = \frac{i f + k}{2} - h, x = - \frac{i f + k}{2} - h

x^{2} + 10 x = 50

x^{2} + 10 x = 25

x^{2} + 10 x = 20

9 x^{2} + 18 x + 5 = 0

x^{2} + 2 k x + (k - 1) (k - 3) = 0

What are the solutions to the equation solvefor x,f=-4(x+h)^2-k ?
The solutions to the equation solvefor x,f=-4(x+h)^2-k are x=(isqrt(f+k))/2-h,x=-(isqrt(f+k))/2-h
Find the zeros of solvefor x,f=-4(x+h)^2-k
The zeros of solvefor x,f=-4(x+h)^2-k are x=(isqrt(f+k))/2-h,x=-(isqrt(f+k))/2-h